Design Compressed String Iterator

Problem

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Solution

public class Solution {

    int index;
    String[] strs;
    int[] counts;

    public StringIterator (String s) {
        this.strs = s.split("\\d+");
        this.counts = Arrays.stream(s.substring(1).split("[a-zA-Z]+")).mapToInt(Integer::parseInt).toArray();
        this.index = 0;
    }

    public char next() {
        if (!hasNext()) return ' ';
        char ch = strs[index].charAt(0);
        if (--counts[index] == 0) index++;
        return ch;
    }

    public boolean hasNext() {
        return index < strs.length;
    }
}

Analysis

In this solution we have int index to mark current character, String[] strs and int[] counts to record corresponding data
The logics used in this solution is pretty straightforward
Notice that, however, how we construct counts using Java 8 Arrays.stream() method